50-16t^2=24

Solution for 50-16t^2=24 equation:

50-16t^2=24

We move all terms to the left:

50-16t^2-(24)=0

We add all the numbers together, and all the variables

-16t^2+26=0

a = -16; b = 0; c = +26;
Δ = b2-4ac
Δ = 02-4·(-16)·26
Δ = 1664
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1664}=\sqrt{64*26}=\sqrt{64}*\sqrt{26}=8\sqrt{26}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{26}}{2*-16}=\frac{0-8\sqrt{26}}{-32}
=-\frac{8\sqrt{26}}{-32}
=-\frac{\sqrt{26}}{-4}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{26}}{2*-16}=\frac{0+8\sqrt{26}}{-32}
=\frac{8\sqrt{26}}{-32}
=\frac{\sqrt{26}}{-4}
$